Subject

Mathematics

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

41.

If α, β are the roots of the equation x2 + bx + c = 0 and aα + h, β + h are the roots of the equation x2 + qx + r = 0, then h is equal to

  • b + q

  • b - q

  • 12b + q

  • 12b - q


42.

202 - 3x2 = 4053x2 - 2, then x is equal to

  • ± 32

  • ± 23

  • ± 43

  • ± 54


43.

Each of the roots of the equation x3 - 6x2 + 6x - 5 = 0 are increased by h. So that the new transformed equation does not contain x term, then h is equal to

  • 1

  • 2

  • 12

  • 13


44.

The roots of the equation x3 - 14x2 + 56x - 64 = 9 are in

  • AGP

  • HP

  • AP

  • GP


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45.

If 1 is a multiple root of order 3 for the equation x4 - 2x3 + 2x - 1 = 0, then the other root is

  • 0

  • - 1

  • 1

  • 2


46.

limx0sinxsin-1xx2 is equal to

  • 0

  • 1

  • - 1


47.

The biquadratic equation, two of whose roots are 1 + i, 1 - 2, is

  • x4 - 4x3 + 5x2 - 2x - 2 = 0

  • x4 + 4x3 - 5x2 + 2x + 2 = 0

  • x4 + 4x3 - 5x2 + 2x - 2 = 0

  • x4 + 4x3 + 5x2 - 2x + 2 = 0


48.

iF a is a complex number and b is a real number, then the equation a + a + b = 0 represents a

  • straight line

  • parabola

  • circle

  • hyperbola


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49.

If θ = π6, then the 10th term of  1 + cosθ + isinθ + cosθ + isinθ2 + cosθ + isinθ3 + ...is equal to

  • i

  • - 1

  • 1

  • - i


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50.

sin5θsinθ is equal to 

  • 16cos4θ - 12cos2θ + 1

  • 16cos4θ+ 12cos2θ + 1

  • 16cos4θ - 12cos2θ - 1

  • 16cos4θ + 12cos2θ - 1


A.

16cos4θ - 12cos2θ + 1

sin5θsinθ = sin3θ + 2θsinθ           = sin3θcos2θ + cos3θsin2θsinθ            = 3sinθ - 4sin3θcos2θ + 2cos3θ . sinθcosθsinθ           = 3 - 4sin2θ2cos2θ - 1 + 2cosθ4cos3θ - 3cosθ           = 3 - 41 - cos2θ2cos2θ - 1 +  8cos4θ - 6cos2θ           = 4cos2θ - 12cos2θ - 1 +  8cos4θ - 6cos2θ           = 8cos4θ - 6cos2θ + 1 + 8cos4θ - 6cos2θ + 1           = 16cos4θ - 12cos2θ + 1


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