If the foot of the perpendicular from (0, 0, 0) to the plane is (1, 2, 2), then the equation ofthe plane is
- x + 2y + 8z - 9 = 0
x + 2y + 2z - 9 = 0
x + y + z - 5 = 0
x + 2y - 3z + 1 = 0
B.
x + 2y + 2z - 9 = 0
Now, we take the equation of plane x + 2y + 2z - 9 = 0 Since, it is passing through the point (1, 2, 2).
Thus, the required equation of the plane is
x + 2y + 2z - 9 = 0
A variable plane is at a constant distance h from the origin and meets the coordinate axes in A, B, C. Locus of centroid of ABC is
x2 + y2 + z2 = h- 2
x2 + y2 + z2 = 4h- 2
x2 + y2 + z2 = 16h2