If the angle 20 is acute, then the acute angle between the pair o

Subject

Mathematics

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

1.

From a point on the level ground, the angle of elevation of top of a pole is 30° on moving 20metres nearer,the angle of elevation is 45°. Then,the height of the pole in metres, is

  • 103 - 1

  • 103 - 1

  • 15

  • 20


2.

A bag contains 5 black balls, 4 white balls and 3 red balls. If a ball is selected at random, the probability that it is a black or a red ball, is

  • 13

  • 14

  • 512

  • 23


3.

The probability of getting qualified in IITJEE and EAMCET by a student are respectively 15 and 35. The probability that the student gets qualified for atleast one of these test, is

  • 325

  • 825

  • 1725

  • 2225


4.

One die and a coin (both unbiased) are tossed simultaneously. The probability of getting 5 on the top of the die and tail on the coin is

  • 12

  • 112

  • 16

  • 18


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5.

If the axes are rotated through an angle 45° in the positive direction without changing the origin,then the co-ordinates of the point (2, 4) in the old system are

  • 1 - 22, 1 + 22

  • 1 + 22, 1 - 22

  • 22, 2

  • 2, 2


6.

If a straight line perpendicular to 2x - 3y + 7 = 0 forma triangle with the co-ordinate axes whose area is 3 sq. units, then the equation of the straight line is

  • 3x + 2y = ± 2

  • 3x + 2y = ± 6

  • 3x + 2y = ± 4

  • 3x + 2y = ± 8


7.
  • x2y2/3 + (xy2)23 = 1

  • x2 - y2 = 4xy

  • x2 - y2 = 12xy

  • x2 - y22 = 16xy


8.

If ( - 2, 6) is the image of the point (4, 2) with respect to the line L = 0, then L is equal to

  • 6x - 4y - 7 = 0

  • 2x + 3y - 5 = 0

  • 3x - 2y + 5 = 0 

  • 3x - 2y + 10 = 0


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9.

If the co-ordinate axes are the bisectors of the angles between the pair of lines ax2 + 2hxy + by2 = 0 where h2 >ab and a  b, then

  • a + b = 0 

  • h = 0

  • h  0, a + b = 0

  • a + b  0


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10.

If the angle 20 is acute, then the acute angle between the pair of straight lines x2cosθ - sinθ + 2xycosθ + y2cosθ + sinθ = 0

  • 2θ

  • θ2

  • θ3

  • θ


D.

θ

we havex2cosθ - sinθ + 2xycosθ + y2cosθ + sinθ = 0we know that,tanα = 2h2 - aba + btanα = 2cos2θ - cosθ - sinθcosθ + sinθ   cosθ + sinθ  + cosθ - sinθ          = 2cos2θ - cos2θ + sin2θ 2cosθ = tanθ   α = θ


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