f(x) is a polynomial of degree 2, f(0) = 4, f'(0) = 3 and f''(0) = 4, then f(- 1) is equal to
3
- 2
2
- 3
A.
3
Let the polynomial equation be
f(x) = ax2 + bx + c ...(i)
f'(x) = 2ax + b
and f''(x) = 2a
Given, f(0) = 4, f'(0) = 3 and f''(0) = 4
c = 4 ...(ii)
b = 3 ...(iii)
and 2a = 4
a = 2 ...(iv)
On putting these values in Eq. (i), we get
f(x) = 2x2 + 3x + 4
f(- 1) = 2(- 1)2 + 3(- 1) + 4
= 2 - 3 + 4 = 3
Solution of differential equation sec(x)dy - cosec(y)dx = 0 is
cos(x) + sin(y) = c
sin(x) + cos(y) = 0
sin(y) - cos(x) = c
cos(y) - sin(x) = c
Using Trapezoidal rule and following table is equal to
x | 0 | 0 | 4 | 6 | 8 |
f(x) | 2 | 5 | 10 | 17 | 26 |
184
92
46
- 36