is equal to
- 2
0
2
4
2x - ex - 4xex + c
2x - 4x + 4ex + c
2x + 4x + 4ex + c
1 - 4x ex + c
B.
Given that, I = ∫xexdxPutting x = t ⇒ 12xdx = dt∴ I = 2∫t2etdt = 2t2et - 2tet + 2et + c = 2x - 4x + 4ex + c
∫dxx2 + 2x + 2 is equal to
sin-1x + 1 + c
sinh-1x + 1 + c
tanh-1x + 1 + c
tan-1x + 1 + c