is equal to
- 2
0
2
4
2x - ex - 4xex + c
2x - 4x + 4ex + c
2x + 4x + 4ex + c
1 - 4x ex + c
∫dxx2 + 2x + 2 is equal to
sin-1x + 1 + c
sinh-1x + 1 + c
tanh-1x + 1 + c
tan-1x + 1 + c
D.
We have, ∫dxx2 + 2x + 2 = ∫dxx + 12 + 1∴ ∫tan-1xdx = 11 + x2 + c∴ I = ∫dx1 + x + 12 = tan-1x + 1 + c