A random variable X has Poisson distribution with mean 2. Then P

Subject

Mathematics

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

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71.

A random variable X has Poisson distribution with mean 2. Then P(X > 1.5) equals

  • 2/e2

  • 0

  • 1 minus 3 over straight e squared
  • 1 minus 3 over straight e squared


C.

1 minus 3 over straight e squared
straight P space left parenthesis straight x space equals straight k right parenthesis space equals space straight e to the power of negative straight lambda end exponent space fraction numerator straight lambda to the power of straight k over denominator straight k factorial end fraction
straight P left parenthesis straight x space greater or equal than space 2 right parenthesis space space equals 1 space minus space straight P space left parenthesis straight x space equals 0 right parenthesis space minus space straight P space left parenthesis straight x space equals 1 right parenthesis
space equals space 1 minus straight e to the power of negative straight lambda end exponent space minus straight e to the power of negative straight lambda end exponent space open parentheses fraction numerator straight lambda over denominator 1 factorial end fraction close parentheses
space equals space 1 minus 3 over straight e squared
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72.

A and B are two like parallel forces. A couple of moment H lies in the plane of A and B and is contained with them. The resultant of A and B after combining is displaced through a distance

  • 2H/A-B

  • H/A+B

  • H/2(A+B)

  • H/2(A+B)

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73.

The resultant R of two forces acting on a particle is at right angles to one of them and its magnitude is one-third of the other force. The ratio of larger force to smaller one is 

  • 2 : 1

  • 3 colon square root of 2
  • 3:2

  • 3:2

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74.

The plane x + 2y – z = 4 cuts the sphere x2 + y2 + z2 – x + z – 2 = 0 in a circle of radius

  • 3

  • 1

  • 2

  • 2

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75.

Let x1, x2, …,xn be n observations such that sum from space to space of straight x subscript straight i superscript 2 space equals space 400 space and space stack sum space with space below and space on top straight x subscript straight i space equals space 80 Then a possible value of n among the following is

  • 15

  • 18

  • 19

  • 19

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