Subject

Mathematics

Class

JEE Class 12

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

61.

cos-37xsin-117xdx is equal to:

  • logsin47x + c

  • 47tan47x + c

  • - 74tan-47x + c

  • logcos37x + c


62.

sinθ + cosθsin2θ is equal to :

  • logcosθ - sinθ + sin2θ

  • logsinθ - cosθ + sin2θ

  • sin-1sinθ - cosθ

  • sin-1sinθ + cosθ


63.

π6π3dx1 + tanx is equal to :

  • π12

  • π2

  • 3π2

  • 2π


64.

- ππsin4xsin4x + cos4xdx is equal to :

  • π

  • π2

  • 3π2

  • 2π


Advertisement
65.

The value of 2sinx2sinx + 2cosxdx is :

  • 2

  • π

  • π4

  • 2π


66.

If f is continuous function, then :

  • - 22fxdx = 02fx - f- xdx

  • - 352fxdx = - 610fx - 1dx

  • - 35fxdx = - 44fx - 1dx

  • - 35fxdx = - 26fx - 1dx


Advertisement

67.

The area of the region bounded by y2 = 4ax and x2 = 4ay, a > 0 in sq unit, is :

  • 16a23

  • 14a23

  • 13a23

  • 16a2


A.

16a23

The equations of given curves are
y2 = 4ax and x2 = 4ay

On solving these equations, we get

(0, 0) and (4a, 4a)

 Required area

    = 04a2ax - x24adx= 2ax3232 - x312a04a= 323a2 - 16a23= 16a23 sq unit


Advertisement
68.

An integrating factor of the differential equation xdydx + ylogx = xexx12logx, (x > 0) is :

  • xlog(x)

  • xlogx

  • elogx2

  • ex2


Advertisement
69.

The solution of edydx = x + 1, y(0) = 3 is :

  • y = xlog(x) - x + 2

  • y = (x + 1)logx + 1 - x + 3

  • y = x + 1logx + 1 + x + 3

  • y = xlogx + x + 3


70.

Solution of the differential equation dydxtany = sinx + y + sinx - y is :

  • secy + 2cosx = c

  • secy - 2cosx = c

  • cosy - 2sinx = c

  • tany - 2secy = c


Advertisement