The solution of the differential equation xdy - yd

Subject

Mathematics

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

31.

The solution of the differential equation  is :

  • y(1 + x2) = c + tan-1(x)

  • y1 + x2 = c + tan-1x

  • y1 + x2 = c + sin-1x


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32.

The solution of the differential equation xdy - ydx = x2 + y2dx is :

  • x+  x2 + y2 = cx2

  • y-  x2 + y2 = cx

  • x -  x2 + y2 = cx

  • y+  x2 + y2 = cx2


D.

y+  x2 + y2 = cx2

xdy - ydx = x2 + y2dx xdy = x2 + y2dx + ydx xdy = x2 + y2 + ydx dydx = x2 + y2 + yxNow, put y = vx  dydx = v + xdvdx v + xdvdx = x2 + v2x2 + vxx                    = x1 + v2 + vxx             xdvdx = 1 + v2 dv1 + v2 = dxx logv + 1 + v2 = logx + logc               On putting v = yx     y +  x2 + y2 = cx2


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33.

The solution of the differential equation dydx = ex - y + x2e- y is :

  • y = ex - y + x2e- y + c

  • ey - ex = 13x3 + c

  • ey + ex = 13x3 + c

  • ex - ey = 13x3 + c


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