The solution of the differential equation xdy - yd

Subject

Mathematics

Class

JEE Class 12

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

81.

The value of the integral - π4π4sin- 4xdx is

  • - 83

  • 32

  • 83

  • None of these


Advertisement

82.

The solution of the differential equation xdy - ydx = x2 + y2dx is

  • x + x2 + y2 = cx2

  • y - x2 + y2 = cx2

  • x - x2 + y2 = cx

  • y + x2 + y2 = cx2


D.

y + x2 + y2 = cx2

Given that, xdy - ydx = x2 + y2dx

 xdy = x2 + y2 + y dydx = x2 + y2 + yxNow, put y = vx dydx = v + xdvdx v +xdvdx = x2 + v2x2 + vxx xdvdx = 1 + v2 + v - v dv1 + v2 = dxxOn integrating both sidesdv1 + v2 = dxx      logv + 1 + v2 = logx + logC yx + 1 + yx2 = xC            y + x2 + y2 = x2C


Advertisement
83.

The differential equation of all non-vertical lines in a plane is

  • d2ydx2 = 0

  • d2xdy2 = 0

  • dydx = 0

  • dxdy = 0


84.

x + 2x + 42exdx is equal to

  • exxx + 4 +C

  • exx + 2x + 4 +C

  • exx - 2x + 4 +C

  • ex2xexx + 4 +C


Advertisement
85.

The value of 35x2x2 - 4dx

  • 2 - loge157

  • 2 + loge157

  • 2 + 4loge3 - 4loge7 + 4loge5

  • 2 - tan-157


86.

0dxx +x2 +13 is equal to

  • 38

  • 18

  • - 38

  • None of these


87.

A common tangent to 9x2 - 16y2 = 144 and x2 + y2 = 9 is

  • y = 37x + 157

  • y = 327x + 157

  • y = 237x + 157

  • None of these


88.

The differential equation of all parabolas whose axes are parallel to y-axis is

  • d3ydx3 = 0

  • d2xdy2 = 0

  • d3ydx3+ d2xdy2 = 0

  • d2ydx2 + 2dydx = 0


Advertisement
89.

The locus of a point P which moves such that 2PA = 3PB, where A(0, 0) and B(4,- 3) are points, is

  • 5x2 - 5y2 - 72x + 54y + 225 = 0

  • 5x2 + 5y2 - 72x + 54y + 225 = 0

  • 5x2 + 5y2 + 72x - 54y + 225 = 0

  • 5x2 + 5y2 - 72x - 54y - 225 = 0


90.

The points P is equidistant from A(1, 3), B (- 3, 5) and C(5, - 1), then PA is equal to

  • 5

  • 55

  • 25

  • 510


Advertisement