Subject

Mathematics

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

61.

12 + 1 + 22 + 2 + 32 + 3 + ... + n2 + n is equal to

  • nn + 12

  • nn + 122

  • nn + 1n + 23

  • nn + 1n + 2n + 34


62.

21/4 . 41/8 . 81/16 . 161/32 ... is equal to

  • 1

  • 2

  • 32

  • 52


63.

The locus of the points z which satisfy the condition argz - 1z + 1 = π3

  • a straight line

  • a circle

  • a parabola

  • None of the above


64.

The sides of triangle are in the ratio 1 : √3 : 2, then the angles of the triangle are in ratio

  • 1 : 3 : 5

  • 2 : 3 : 1

  • 3 : 2 : 1

  • 1 : 2 : 3


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65.

limx0ax - bxex - 1 is equal to 

  • logeab

  • logeba

  • logeab

  • logea + b


66.

If α + β - γ = π, then sin2α + sin2β - sin2γ is equal to

  • 2sinαsinβcosγ

  • 2cosαcosβcosγ

  • 2sinαsinβsinγ

  • None of the above


67.

The range of the function f (x) = Px - 37 - x is

  • {1, 2, 3}

  • {1, 2, 3, 4, 5, 6}

  • {1, 2, 3, 4}

  • {1, 2, 3, 4, 5}


68.

The maximum value of xy subject to x + y = 8

  • 8

  • 16

  • 20

  • 24


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69.

A particle moves along a straight line according to the laws = 16- 2t + 3t, where s metres is the distance of the particle from a fixed point at the end of t seconds. The acceleration of the particle at the end of 2s is

  • 36m/s2

  • 34m/s2

  • 36m

  • None of these


A.

36m/s2

Given, s = 16 - 2t + 3t3

   dsdt = - 2 + 9t2and d2sdt2 = 18t  Acceleration at the end oft second is (18 t) m/sAt t = 2s, , acceleration a = d2sdt2 = 18 × 2 a = 36m/s2


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70.

tan-1xy - tan-1x - yx + y is equal to (where x > y > 0)

  • - π4

  • π4

  • 3π4

  • None of these


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