Find the general solution of secθ + 1 =

Subject

Mathematics

Class

JEE Class 12

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 Multiple Choice QuestionsShort Answer Type

81.

If A = 1201, then by the principle of Mathematical induction, prove that An12n01


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82.

Find the general solution of secθ + 1 = 2 + 3tanθ


Given, secθ + 1 = 2 + 3tanθOn squaring both sides, we get        secθ + 12 = 2 + 32tan2θ    secθ + 12 = 4 + 3 + 43sec2θ - 1 secθ + 1secθ + 1 - 7 + 43secθ - 1 = 0            secθ + 18 + 43 - 6 + 43secθ = 0                       secθ + 1 = 0or 8 + 43 - 6 + 43 = 0 cosθ = 32 = cosπ6        θ = 2 ± π6But θ = 2 - π6 does not satisfying the given equation.

 θ = 2 ± π, 2 + π6, n  I


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83.

Prove that for all values of m, except zero the straight line

y =  mx + am touches the parabola y2 = 4ax.


84.

If the tangent to the parabola y = x(2 - x) at the point (1, 1) intersects the parabola at P. Find the coordinate of P.


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85.

If an unbiased coin is tossed n times. Find the probability that head appears an odd number of times.


86.

Evaluate x2x1 +x2dx


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