The area bounded by the curve y2(2a - x) = x3 and the line x = 2a

Subject

Mathematics

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

11.

If function , then the number of points at which f(x) is continuous, is

  • 1

  • 0

  • None of these


12.

If xmyn = (x + y)m + n, then dydx is

  • x +yxy

  • xy

  • xy

  • yx


13.

If ABCDEF is a regular hexagon with AB = a and BC = b, then CE equals

  • b - a

  • - b

  • b - 2a

  • None of these


14.

Magnitudes of vectors a, b, c are 3, 4, 5 respectively. If a and b + c, b and c + a and c and a + b  are mutually perpendicular, then magnitude of a + b + c is

  • 42

  • 32

  • 52

  • 33


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15.

The differential equation of all circles which passes through the origin and whose centre lies on y-axis is

  • x2 - y2dydx - 2xy = 0

  • x2 - y2dydx + 2xy = 0

  • x2 - y2dydx - xy = 0

  • x2 - y2dydx + xy = 0


16.

If forces P, Q, R acting at a point can be represented by the sides of a triangle taken in order, then

  • P + Q + R = 0

  • P - Q + R = 0

  • P + Q - R = 0

  • P - Q - R = 0


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17.

The area bounded by the curve y2(2a - x) = x3 and the line x = 2a is

  • 3πa2 sq unit

  • 3πa22 sq unit

  • 3πa24 sq unit

  • 6πa25 sq unit


B.

3πa22 sq unit

The equation of curve and line are respectively

y2(2a - x) = x3      ...(i)

and       x = 2a     ...(ii)

The given curve is symmetrical about x-axis and passes through origin.

Also, x32a - x < 0 for x >2a and x < 0

So, curve does not is in x > 2a and x < 0, therefore curve lies wholly on 0  x  2a.

 Required area = 02ax322a - xdxPut x = 2a2sin2θ and dx = 4asinθcosθ

 Required area = 02a8a2sin4θ= 8a234 . 12 . π2         using gamma function= 3πa22 sq unit


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18.

A sphere S1 impings directly on an equal sphere S2 at rest. If the coefficient of restitution is e, then the velocities of S1 and S2 are in the ratio

  • 1 + e1 - e

  • 1 - e1 + e

  • e - 1e + 1

  • e + 1e - 1


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19.

If aa21 + a3bb21 + b3cc21 + c3 = 0 and the vectors A = 1, a, a2, B = 1, b, b2 and C = 1, c, c2 are non- coplana, then abc is equal to

  • 0

  • - 1

  • 1

  • None of these


20.

The magnitude of the two forces forming a couple is 36 N each and the arm of the couple is 4m. The magnitude of each force of an equivalent couple whose arm is 9m, is (in Newtons)

  • 18

  • 26

  • 16

  • 15


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