In triangle ABC, a = 2, b = 3 and sin(A) = , then B is equal to
30
60
90
120
C.
90
By using sine rules, we get
The circles x2 + y2 - 10x + 16 = 0 and x2 + y2 = a2 intersect at two distinct points, if
a < 2
2 < a < 8
a > 8
a = 2
The number of points on the line x + y = 4 which are unit distance apart from the line 2x + 2y = 5 is
0
1
2
If three positive real numbers a, b, c are in AP and abc = 4, then the minimum possible value of b is 2