Subject

Mathematics

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

41.

The distance of the point of intersection of the line x - 23 = y + 14 = z - 212 and the plane x - y + z = 5 from the point (- 1, - 5, - 10)is

  • 13

  • 12

  • 11

  • 8


42.

If the direction cosines of a line are 1c, 1c, 1c, then

  • 0 < c < 1

  • c > 2

  • c = ± 2

  • c = ± 3


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43.

The vector form of the sphere 2(x2 + y2 + z2) - 4x + 6y + 8z - 5 = 0 is

  • r . r - 2i^ + j^ + k^ = 25

  • r . r - 2i^ - 3j^ - 4k^ = 12

  • r . r - 2i^ + 3j^ + 4k^ = 52

  • r . r - 2i^ - 3j^ - 4k^ = 52


D.

r . r - 2i^ - 3j^ - 4k^ = 52

Given equation can be rewritten as

x2 + y2 + z2 - 2x + 3y + 4z - 52 = 0

Let r = x i^ + y j^ + z k^ = 52

Thus, given equation written in vector form is

r . r - 2i^ - 3j^ - 4k^ = 52


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44.

If the lines 1 - x3 = y - 22α = z - 32x - 13α = y - 1 = 6 - z5 are perpendicular, then the value of α is

  • - 107

  • 107

  • - 1011

  • 1011


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45.

The distance between the lines r = 4i^ - 7j^ - 9k^ + t3i^ - 7j^ + 4k^ and r = 7i^ - 14j^ - 5k^ + s- 3i^ + 7j^ - 4k^ is equal to

  • 1

  • 12

  • 34

  • 0


46.

x31 + x435dx is equal to

  • 1 + x3465 + c

  • 1 + x4365 + c

  • 581 + x4365 + c

  • 161 + x436 + c


47.

If u = - f''θsinθ + f'θcosθ and v = f''θcosθ + f'θsinθ, then du2 + dv212 is equal to

  • fθ - f''θ + c

  • fθ + f''θ + c

  • f'θ + f''θ + c

  • f'θ - f''θ + c


48.

e6logex - e5logexe4logex - e3logexdx is equal to

  • x33 + c

  • x22 + c

  • x23 + c

  • - x33 + c


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49.

ex1 - x1 + x22dx is equal to

  • ex1 - x1 + x2 + c

  • ex11 + x2 + c

  • ex1 + x1 + x2

  • ex1 - x1 + x22 + c


50.

x4 - 1x2x4 + x2 + 112dx is equal to

  • x4 + x2 + 1x + c

  • x2x4 + x2 + 1 + c

  • xx4 + x2 + 132 + c

  • x4 + x2 + 1x + c


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