If A = 1111, then A100 is equal to from Mathematics JEE Yea

Subject

Mathematics

Class

JEE Class 12

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

1.

The length of the normal to the curve x = aθ + sinθ, y =  a1 - cosθ at θ = π2 is

  • 2a

  • a2

  • a2

  • 2a


2.

The maximum value of logxx is

  • e

  • 2e

  • 1e

  • 2e


3.

In the interval - π4, π4, the number of real solutions of the equations sinxcosxcosxcosxsinxcosxcosxcosxsinx = 0 is

  • 0

  • 2

  • 1

  • 3


4.

If f(x) = xsin1x, x  0k           , x = 0 is continuous at x = 0, then the value of k will be

  • 1

  • - 1

  • 0

  • None of these


Advertisement
5.

If cotcos-1x = sectan-1ab2 - a2, then x is equal to

  • b2b2 - a2

  • a2b2 - a2

  • 2b2 - a2a

  • 2b2 - a2b


6.

Number of solutions ofthe equation

tan-112x + 1 + tan-114x + 1 = tan-12x2 is

  • 1

  • 2

  • 3

  • 4


7.

If f(x) = 4x4x + 2, then f197 + f297 + ... + f9697 is equal to

  • 1

  • 48

  • - 48

  • - 1


8.

If f(x) = xpcos1x, x  00             , x = 0 is differentiable at x = 0, then

  • p < 0

  • 0 < p < 1

  • p = 1

  • p > 1


Advertisement
9.

If xx21 +x3yy21 + y3zz21 + z3 = 0 and x, y, z are all distinct, then xyz is equal to

  • - 1

  • 1

  • 0

  • 3


Advertisement

10.

If A = 1111, then A100 is equal to

  • 100 A

  • 299 A

  • 2100 A

  • 99 A


B.

299 A

Since, A = 1111Now, A2 = 11111111 = 2222             = 21111 = 2AAgain, now A3 = A . A2                       = A. 2A = 2A2 = 22ASimilarly, A100 = 299A


Advertisement
Advertisement