If the displacement, velocity and acceleration of a particle at time t be x, v and f respectively, then which one is true ?
The displacement x of a particle at time t is given by x = At2 + Bt + C where A, B, C are constants and v is velocity of a particle, then the value of 4Ax - v2 is
4AC + B2
4AC - B2
2AC - B2
2AC + B2
The displacement of a particle at time t is x, where x = t4 - kt3. If the velocity of the particle at time t = 2 is minimum, then
k = 4
k = - 4
k = 8
k = - 8
The general solution of the differential equation
is
y = (c1 + c2x)ex
y = (c1 + c2x)e- x
y = c1ex + c2e- x
If y'' - 3y' + 2y = 0 where y(0) = 1, y'(0) = 0, then the value of y at x = log(2) is
1
- 1
2
0
D.
0
The corrosponding equation is m2 - 3m + 2 = 0
General solution of given equation is,
y = Aex + Be2x
y' = Aex + 2Be2x
At x = 0, y = 1
and x = 0, y' = 0
Solving these equation A = 2, B = 1