The middle term in the expansion of ba5 - 5ab12&nb

Subject

Mathematics

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

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1.

The middle term in the expansion of ba5 - 5ab12 is

  • C612ba3

  • - C612ba3

  • C712ba5

  • - C712b5a


A.

C612ba3

Given, ba5 - 5ab12Middle term = n2 + 1th term      n is even Tn2 + 1 = Cn2nba5n2 = - 5abn2 T7 = C612ba56- 5ab6           = C612 b6a3a6b3           = C612ba3Hence, middle term is C612ba3.


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2.

If in an AP, 3rd term is 18 and 7th term is 30, the sum of its 17 terms is

  • 600

  • 612

  • 624

  • None of these


3.

The sum of the digitsin the unit place of all the numbers formed with the help of 3, 4, 5, 6 taken all at a time is

  • 432

  • 108

  • 36

  • 18


4.

The number of solutions of x2 + 3x + 2 = 0 the equation is

  • 0

  • 1

  • 2

  • 4


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5.

In a throw of two dice, the probability of getting a sum of 7 or 11 is

  • 29

  • 79

  • 59

  • None of these


6.

The probability that at least one of the events A and B occurs is 0.7 and they occur simultaneously with probability 0.2. Then, PA + PB is equal to

  • 0.8

  • 0.6

  • 1.1

  • 1.4


7.

If sinθ + cscθ = 2, then sin2θ + csc2θ is equal to

  • 1

  • 4

  • 2

  • None of these


8.

The maximum value of 5cosθ + 3cosθ + π3 + 3 is

  • 10

  • - 10

  • 14

  • None of these


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9.

If α and β are the solutions of atanθ + bsecθ = c, then tanα + β is equal

  • 2aca2 - c2

  • 2acc2 - a2

  • 2aca2 + c2

  • None of these


10.

If sin-1x5 + csc-154 = π2, then x is equal to

  • 4

  • 5

  • 1

  • 3


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