Subject

Mathematics

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

31.

If the vector 8i + aj of magnitude 10 is in the direction of the vector 4i + 3j, then the value of equal to

  • 6

  • 3

  • - 3

  • - 6


32.

If a = 2i - 7j + k and b = i + 3j - 5k and a · mb = 120, then the value of m is equal to

  • 5

  • - 24

  • - 5

  • 120


33.

If the angle between a and c is 25°, the angle between b and c is 65° and a + b = c, then the angle between a and b is

  • 40°

  • 115°

  • 25°

  • 90°


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34.

The position vector of the centroid of the ABC is 2i + 4 j + 2k. If the position vector of the vertex A is 2i + 6j + 4k, then the position vector of midpoint of BC is

  • 2i + 3j + k

  • 2i + 3j - k

  • 2i - 3j - k

  • - 2i - 3j - k


A.

2i + 3j + k

Given, the position vector of vertex A = 2i + 6j + 4k and centroid of ABC = 2i + 4j + 2k.

We know that the median AM of ABC divided by centroid G, in the ratio 2 : 1.

Then, by section formula

2, 4, 2 = 2x +22 + 1, 2y +62 + 1, 2z + 42 + 1

On comparing,

 2x + 2 = 6           x = 2 2x + 6 = 12          y = 3 2z + 4 = 6          z = 1

So, the position vector of M i.e., mid point of BC is

              = 2i + 3j + k


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35.

The projection of the vector 2i + aj - k on the vector i - 2j + k is - 56. Then, the value of a is equal to

  • 1

  • 2

  • - 2

  • 3


36.

A unit vector in the XOY-plane that makes an angle 30° with the vector i + j and makes an angle 60° with i - j is

  • 146 + 2i - 6 - 2j

  • 126 - 2i + 6 + 2j

  • 146 - 2i + 6 + 2j

  • 146 + 2i + 6 - 2j


37.

The angle between the line r = (i + 2j + 3k) + λ(2i + 3j + 4k) and the plane r - (i + j - 2k) = 0 is

  • 60°

  • 30°

  • 90°


38.

The lines r = i + j - k + (3i - j) and r = 4j - k + µ (2i + 3k) intersect at the point

  • (0, 0, 0)

  • (0, 0, 1)

  • (0, - 4, - 1)

  • (4, 0, - 1)


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39.

An equation of the plane through the points (1, 0, 0) and (0, 2, 0) and at a distance 67 units from the origin is

  • 6x + 3y + z - 6 = 0

  • 6x + 3y + 2z - 6= 0

  • 6x + 3y + z + 6 = 0

  • 6x + 3y + 2z + 6 = 0


40.

The projection of a line segment on the axes are 9, 12 and 8. Then, the length of the line segment is

  • 15

  • 16

  • 17

  • 18


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