A unit vector perpendicular to both i + j + k and 2i + j + 3k is
2i - j - k
3i + j - 2k6
The value of ∫04x - 1dx is
52
5
4
1
If In = ∫0π4tannxdx, where where n is apositive integer, then I10 + I8 is
19
18
17
9
If In = ∫exsinx + cosx1 - sin2xdx is
ex . cscx + C
ex . cotx + C
ex . secx + C
ex . tanx + C
When x > 0, then ∫cos-11 - x21 + x2dx is
2xtan-1x - log1 + x2 + C
2xtan-1x + log1 + x2 + C
If the area between y = mx2 and x = my2 (m > 0) is 1/4 sq units, then the value of m is
± 32
± 23
2
3
B.
Given curves; y = mx2 and y2m= x; m > 0Intersection point of both curves x = mmx22 = m3x4⇒ m3x4 - x = 0⇒ xm3x3 - 1 = 0⇒ xmx - 1m2x2 + 1 + mx = 0⇒ x = 0, x = 1/m and y = 0, y = 1/mWe take only the points = (0, 0) and (1/m, 1/m)Now, the area of the curve= ∫01mxm - mx2dxGiven, 14 = 23m . x32 - m . x3301m⇒ 14 = 23m . 1m32 - m3 . 1m3⇒ 14 = 23m2 - 13m2⇒ 14 = 13m2⇒ m2 = 43∴ m = ± 23
If m and n are degree and order of 1 + y1223 = y2, then the value of m + nm - n is
The general solution of dydx2 = 1 - x2 - y2 + x2y2 is
2sin-1y = x1 - x2 + sin-1x + C
cos-1y = xcos-1x + C
sin-1y =12sin-1x + C
2sin-1y = x1 - y2 + C