Subject

Mathematics

Class

JEE Class 12

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

21.

A vehicle registration number consists of 2 letters of English alphabet followed by 4 digits, where the first digit is not zero. Then, the total number of vehicles with distinct registration numbers is

  • 262 × 104

  • P226 × P410

  • P226 × 9 × P310

  • P226 × 9 × 103


22.

The number of words that can be written using all the letters of the word 'IRRATIONAL' is

  • 10!2!3

  • 10!2!2

  • 10!2!

  • 10!


23.

Four speakers will address a meeting where speaker Q will always speak P. Then, the number of ways in which the order of speakers can be prepared is

  • 256

  • 128

  • 24

  • 12


24.

The number of diagonals in a regular polygon of 100 sides is

  • 4950

  • 4850

  • 4750

  • 4650


Advertisement
25.

Let the coefficients of powers of x in the 2nd, 3rd and 4th terms in the expansion of (1 + x)n, where n is a positive integer, be in arithmetic progression. Then, the sum of the coefficients of odd powers of x in the expansion is

  • 32

  • 64

  • 128

  • 256


26.

Let f(x) = ax2 + bx + c, g(x) = px2 + qx + r such that f(1) = g(1), f(2) = g(2) and f(3) - g(3) = 2. Then, f(4) - g(4) is

  • 4

  • 5

  • 6

  • 7


27.

The sum 1 x 1! + 2 x 2! + ... + 50 x 50! equals

  • 51!

  • 51! + 1

  • 51! + 1

  • × 51!


28.

Six numbers are in AP such that their sum is 3. The first term is 4 times the third term. Then, the fifth term is

  • - 15

  • - 3

  • 9

  • - 4


Advertisement
29.

The sum of the infinite series 1 +13 + 1 . 33 . 6 +1 . 3 . 53 . 6 . 9 + 1 . 3 . 5 . 73 . 6 . 9 . 12 + ... is equal to

  • 2

  • 3

  • 32

  • 13


Advertisement

30.

The equations x2 + x + a= 0 and x2 + ax + 1 = 0 have a common real root

  • for no value of a

  • for exactly one value of a

  • for exactly two value of a

  • for exactly three value of a


B.

for exactly one value of a

Let α be the common roots

        α2 +α +a = 0            ...(i)and    α2 + +a = 0            ...(ii)α21 - a2 = αa - 1 = 1a - 1a  1Eliminating α, we get                         a - 12 = 1 - a2a - 1                        a - 1 = 1 - a2               a2 + a - 2 = 0       a2 + 2a - a - 2 = 0 aa + 2 - 1a + 2 = 0           a + 2a - 1 = 0                                 a = - 2                    a  1


Advertisement
Advertisement