Subject

Mathematics

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

41.

A point moves in such a way that the difference of its distance from two points (8, 0) and (- 8, 0) always remains 4. Then, the locus of the point is

  • a circle

  • a parabola

  • an ellipse

  • a hyperbola


42.

The number of integer values of m, for which the x - coordinate of the point of intersection of the lines 3x + 4y= 9 and y =mx + 1 is also an integer, is

  • 0

  • 2

  • 4

  • 1


43.

If a straight line passes through the point (α, β) and the portion of the line intercepted between the axes is divided equally at that point, then xα + yβ is

  • 0

  • 1

  • 2

  • 4


44.

The coefficient of x10 in the expansion of 1 + (1 + x) + ... + (1 + x)20

  • C919

  • C1020

  • C1121

  • C1222


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45.

Let A and B be two events with PAC = 0.3, P(B) = 0.4 and PA  BC. Then, PB | A  BC is equal to

  • 14

  • 13

  • 12

  • 23


46.

Let p, q and r be the altitudes of a triangle with area S and perimeter 2 t. Then, the value of 1p + 1q + 1r is

  • St

  • tS

  • S2t

  • 2St


47.

Let C1 and C2 denote the centres of the circles x2 + y= 4 and (x - 2)2 + y2 = 1 respectively and let P and Q be their points of intersection. Then, the areas of C2PQ and CPQ are in the ratio

  • 3 : 1

  • 5 : 1

  • 7 : 1

  • 9 : 1


48.

A straight line through the point of intersection of the lines x + 2y = 4 and 2x + y = 4 meets the coordinate axes at A and B. The locus of the mid-point of AB is

  • 3(x + y) = 2xy

  • 2(x + y) = 3xy

  • 2(x + y) = xy

  • x + y = 3xy


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49.

Let P and Q be the points on the parabola y2 = 4x so that the line segment PQ subtends right angle at the vertex. If PQ intersects the axis of the parabola at R, then the distance of the vertex from R is

  • 1

  • 2

  • 4

  • 6


C.

4

According to question, it is given that slope of PX and QX are perpendicular to each other, i.e., slope of PX x slope of XQ = - 1

 2tt2 × 2mm2 = - 1              tm = - 4PQ : x - t2t2 - m2 = y - 2t2t - 2m

Let PQ meets axis of parabola i.e., x - axis at Rα, 0, then

α - t2t + mt - m = 0 - 2t2t - m α - t2 = - t2 - tm = - t2 + 4 α = 4  AR = 4


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50.

The incentre of an equilateral triangle is (1, 1) and the equation of one side is 3x + 4y + 3 = 0. Then, the equation of the circumcircle of the triangle is

  • x2 + y2 - 2x - 2y - 2 = 0

  • x2 + y2 - 2x - 2y - 14 = 0

  • x2 + y2 - 2x - 2y + 2 = 0

  • x2 + y2 - 2x - 2y + 14 = 0


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