Let y be the solution of the differential equation
satisfying y(1) = 1. Then, y satisfies
y = xy - 1
y = xy
y = xy + 1
y = xy + 2
The area of the region, bounded by the curves y = sin- 1(x) + x(1 - x) and y = sin- 1 (x) - x(1 - x) in the first quadrant, is
1
C.
is defined, if
In first quadrant
On solving, we get
2x(1 - x) = 0
Let [x] denote the greatest integer less than or equal to x, then the value of the integral is equal to
3
2
- 2
- 3