A point moves in the xy-plane such that the sum of its distance from two mutually perpendicular lines is always equal to 5 units. The area(in sq units) enclosed by the locus of the point,is
25
50
100
If the foot of the perpendicular from (0, 0, 0) to a plane is (1, 2, 3), then the equation of the plane is
2x + y + 3z = 14
x + 2y + 3z = 14
x + 2y + 3z + 14 = 0
x + 2y - 3z = 14
The area (in sq units) bounded by the curves y2 = 4x and x2 = 4y is
B.