A and B are two independent events. Probability of happening of b

Subject

Mathematics

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

41.

The differential equation of the family of circles touching the y-axis at the origin is

  • xy' - 2y = 0

  • y'' - 4y' + 4y = 0

  • 2xyy' + x2 = y2

  • 2yy' + y2 = x2


42.

dxx4 - 1 is equal to

  • 14logx - 1x + 1 - 12tan-1x + C

  • logx - 1x + 1 + C

  • 14logx - 1x + 1 + 12tan-1x + C

  • logx - 1x + 1 - 12tan-1x + C


43.

The equation of a straight line parallel to the x-axis is given by

  • x - a1 = y - b1 = z - c1

  • x - a0 = y - b0 = z - c1

  • x - a0 = y - b1 = z - c1

  • x - a1 = y - b0 = z - c0


44.

The shortest distance between the lines

x - 31 = y - 5- 2 = z - 71 and x + 11 = y + 1- 6 = z + 11 is

  • 1229 units

  • 229 units

  • 29 units

  • 1429 units


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45.

Area of the region bounded by the parabola y = x2 and the curve y = x is

  • 3

  • 13

  • 2

  • 12


46.

The angle between the lines x - 23 = y + 1- 2; z= 2 and x - 11 = 2y + 33; z +52 is

  • π3

  • π6

  • π2

  • π4


47.

If a, b and c are three non-zero, non-coplanar vectors, then the value of a x a' + b x b'+ c x c' is

  • 1

  • 0

  • - 1

  • None of the above


48.

If e= 1, e1 = 2.72, e2 = 7.39, e3 = 20.09, e4 = 54.60, then the value of 04exdx using Simpson's rule, will be

  • 5.387

  • 53.87

  • 52.78

  • 53.17


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49.

A and B are two independent events. Probability of happening of both A and B is 1/6 and probability of happening of neither of them is 1/3, then the probability of events A and B are respectively

  • 12 and 13

  • 15 and 16

  • 12 and 16

  • 23 and 14


A.

12 and 13

Given, PA  B = 16 PA . PB = 16        ...i     A and B are independent eventsand PA  B = 13 PA  B = 131 - PA  B = 13 PA  B = 1 - 13 = 23 PA + PB - PA  B = 23 PA + PB - PA . PB = 23 PA + PB = 23 + 16 = 4 + 16 = 56Now, PA - PB = PA + PB2 - 4PA . PB= 562 - 416      from Eqs. (i) and (ii)= 2536 - 46 = 136 = 16

 PA - PB = 16        ...iiiOn adding Eqs. (ii) and (iii), we get    2PA = 56 + 16 = 1 PA = 12On putting values of P(A) in Eq. (iii), we get12 - PB = 16 PB = 12 - 16 = 3 - 16 = 26 PB = 13Hence, P(A) =12 and P(B) = 13


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50.

- 12x3 - xdx is equal to

  • 11

  • 4

  • 114

  • 411


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