The solution of the differential equation (kx - y2 ) dy = (x2 - k

Subject

Mathematics

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

41.

Area bounded by the curves y = ex, y = e- x and the straight line x = 1 is (in sq units)

  • e + 1e - 2

  • e - 1e + 2


42.

The value of the integral 1e1 + logx3xdx is equal to

  • 14

  • 12

  • 34

  • e


43.

The value of the integtral 01x31 + x8dx is equal to

  • π8

  • π4

  • π16

  • π6


44.

The value of 24logttdt is

  • 12log22

  • 52log22

  • 32log22

  • log22


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45.

The solution of the differential equation (kx - y2 ) dy = (x2 - ky) dx is

  • x3 - y3 = 3kxy + C

  • x3 + y3 = 3kxy + C

  • x2 - y2 = 2kxy + C

  • x2 + y2 = 2kxy + C


B.

x3 + y3 = 3kxy + C

Given differential equation is,

(kx - y2)dy = (x2 - ky)dx

  kxdy - y2dy = x2dx - kydx kxdy + ydx = x2dx + y2dy         kdxy = x2dx + y2dyOn integrating both sides, we getkxy = x33 + y33 - C3  x3 + y3 = 3kxy + C


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46.

The solution of the differential equation dydx = ex + 1 is

  • y = e+ C

  • y = x + ex + C

  • y = xex + C

  • y = x(ex + 1) + C


47.

The order and degree of the differential equation d2ydx2 + dydx32 = y are respectively

  • 1, 1

  • 1, 2

  • 1, 3

  • 2, 2


48.

An integrating factor of the differential equation sinxdydx + 2ycosx = 1 is

  • sin2(x)

  • 2sinx

  • logsinx

  • 1sin2x


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