If A and B are foot of perpendicular drawn from point Q(a, b, c) to the planes yz and zx, then equation of plane through the points A, B and O is
If the probability density function of a random variable X is given as
xi | - 2 | - 1 | 0 | 1 | 2 |
P(X = xi) | 0.2 | 0.3 | 0.15 | 0.25 | 0.1 |
then F(0) is equal to
P(X < 0)
P(X > 0)
1 - P(X > 0)
1 - P(X < 0)
C.
1 - P(X > 0)
We know that, cumulative distribution function F(x) = P (X x)
= P(X = 0) + P(X = - 1) + P(X = - 2)
= 0.15 + 0.3 + 0.2 = 0.65
(a) P(X < 0) = P(X = - 1) + (X = - 2)
= 0.3 + 0.2 = 0.5
(b) P(X > 0) = P(X = 1) + P(X = 2)
= 0.25 + 0.1 = 0.35
(c) 1 - P(X > 0) = 1 - 0.35 = 065
1 - P(X > 0) = F(0)
Hence, option (c) is correct.
The particular solution of the differential equation
, when, x = e, y = e2 is
y = exlog(x)
ey = xlog(x)
xy = elog(x)
ylog(x) = ex
M and N are the mid-points of the diagonals AC and BO respectively of quadrilateral ABCD, then AB + AD + CB + CD is equal to
2MN
2NM
4MN
4NM