If A and B are foot of perpendicular drawn from point Q(a, b, c) to the planes yz and zx, then equation of plane through the points A, B and O is
If the probability density function of a random variable X is given as
xi | - 2 | - 1 | 0 | 1 | 2 |
P(X = xi) | 0.2 | 0.3 | 0.15 | 0.25 | 0.1 |
then F(0) is equal to
P(X < 0)
P(X > 0)
1 - P(X > 0)
1 - P(X < 0)
The particular solution of the differential equation
, when, x = e, y = e2 is
y = exlog(x)
ey = xlog(x)
xy = elog(x)
ylog(x) = ex
M and N are the mid-points of the diagonals AC and BO respectively of quadrilateral ABCD, then AB + AD + CB + CD is equal to
2MN
2NM
4MN
4NM
C.
4MN
Let the position vectors of A, B, C, D, M and N are a, b, c, d, m and n .
Since, M and N are the mid-points of AC and BO.
Now, AB + AD + CB + CD
= (b - a) + (d - a) + (b - c) + (d - c)
= 2(b + d) - 2(a + c)
= 2 2n - 2 2m
= 4(n - m) = 4MN