If , then f(x) at x = 0 is
continuous but not differentiable
not continuous but differentiable
continuous and differentiable
not continuous and not differentiable
The objective function z = 4x1 + 5x2, subject to 2x1 + x2 7, 2x1 + 3x2 15, x2 3, x1x2 0 has minimum value at the point
on X-axis
on Y-axis
at the origin
on the line parallel to X-axis
A.
on X-axis
Given objective function is minimise, z = 4x1 + 5x2
Subject to constraints, 2x1 + x2 7, 2x1 + 3x2 15, x2 3, x1x2 0
Table for line 2x1 + x2 = 7 is
x1 | 0 | 1 | 2 | 3 |
x2 | 7 | 5 | 3 | 1 |
Table for line 2x1 + 3x2 = 15 is
x1 | 0 | 3 | 6 |
x2 | 5 | 3 | 1 |
Now, the value of z at corner points are given below :
Corner points z = 4x1 + 5x2
A(3.5, 0) | z = 4 x 3.5 + 5 x 0 = 14(minimum) |
B(7.5, 0) | z = 4 x 7.5 + 5 x 0 = 30 |
C(3, 3) | z = 4 x 3 + 5 x 3 = 27 |
D(2, 3) | z = 4 x 2 + 4 x 3 = 20 |
Hence, the minimum value of z is 14 at (3.5, 0) i.e. at X-axis.
If the origin and the points P(2, 3, 4 ), Q(1, 2, 3) and R(x, y, z) are coplanar, then
x - 2y - z = 0
x + 2y + z = 0
x - 2y + z = 0
2x - 2y + z = 0
If lines represented by equation px2 - qy2 = 0 are distinct, then
pq > 0
pq < 0
pq = 0
p + q = 0