Subject

Mathematics

Class

JEE Class 12

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

11.

If fx = x for  x 0= 0 for x > 0, then f(x) at x = 0 is

  • continuous but not differentiable

  • not continuous but differentiable

  • continuous and differentiable

  • not continuous and not differentiable


12.

The value of cos-1cotπ2 + cos-1sin2π3 is

  • 2π3

  • π3

  • π2

  • π


Advertisement

13.

The objective function z = 4x1 + 5x2, subject to 2x1 + x2  7, 2x1 + 3x2  15, x2  3, x1x2  0 has minimum value at the point

  • on X-axis

  • on Y-axis

  • at the origin

  • on the line parallel to X-axis


A.

on X-axis

 Given objective function is minimise, z = 4x1 + 5x2

Subject to constraints, 2x1 + x2  7, 2x1 + 3x2  15, x2  3, x1x2  0

Table for line 2x1 + x2 = 7 is

x1 0 1 2 3
x2 7 5 3 1

Table for line 2x1 + 3x2 = 15 is

x1 0 3 6
x2 5 3 1

Now, the value of z at corner points are given below :

Corner points z = 4x1 + 5x2

A(3.5, 0) z = 4 x 3.5 + 5 x 0 = 14(minimum)
B(7.5, 0) z = 4 x 7.5 + 5 x 0 = 30
C(3, 3) z = 4 x 3 + 5 x 3 = 27
D(2, 3) z = 4 x 2 + 4 x 3 = 20

Hence, the minimum value of z is 14 at (3.5, 0) i.e. at X-axis.


Advertisement
14.

01xtan-1xdx =

  • π4 + 12

  • π4 - 12

  • 12 - π4

  • - π4 - 12


Advertisement
15.

If 19 - 16x2dx = αsin-1βx + c, then α + 1β =

  • 1

  • 712

  • 1912

  • 912


16.

The solution of the differential equation

dydx = tanyx + yx is

  • cosyx = cx

  • sinyx = cx

  • cosyx = cy

  • sinyx = cy


17.

If 0π2logcosxdx = π2log12, then 0π2logsecxdx =

  • π2log12

  • 1 - π2log12

  • 1 + π2log12

  • π2log2


18.

If the angle between the planes r . mi^ - j^ + 2k^ + 3 = 0 and r . 2i^ - mj^ - k^ - 5 = 0 is π3, then m =

  • 2

  • ± 3

  • 3

  • - 2


Advertisement
19.

If the origin and the points P(2, 3, 4 ), Q(1, 2, 3) and R(x, y, z) are coplanar, then

  • x - 2y - z = 0

  • x + 2y + z = 0

  • x - 2y + z = 0

  • 2x - 2y + z = 0


20.

If lines represented by equation px2 - qy2 = 0 are distinct, then

  • pq > 0

  • pq < 0

  • pq = 0

  • p + q = 0


Advertisement