The equation of displacement of a particle is x(t) = 5t2 - 7t + 3. The acceleration at the moment when its velocity becomes 5 m/sec is
3 m/sec2
7 m/sec2
10 m/sec2
8 m/sec2
C.
10 m/sec2
We have,
x(t) = 5t2 - 7t + 3 ...(i)
By differentiating both side w.r.t. 't', we get
Velocity ofthe particle,
...(ii)
We have to find acceleration at the moment, when velocity becomes 5 m/sec
From Eq. (ii), we get
10t - 7 = 5
Now, on differentiationg both side of Eq. (11) w.r.t. 't', we get acceleration of the particle
Here, acceleration is constant all the time,
The function
increases in (0, 1) but decreases in (1, 2)
decreases in (0, 2)
increases m (1, 2) but decreases in (0, 1)
increases in (0, 2)
Let f(x) =
For what values of A and B, the function f(x) is continuous throughout the real line ?
A = - 1, B = 1
A = - 1, B = - 1
A = 1, B = - 1
A = 1, B = 1