Subject

Mathematics

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

41.

The angle between the two circles, each passing through the centre of the other is

  • 2π3

  • π2

  • π6

  • π


42.

If log13z2 - z + 12 + z > - 2, then z lies inside

  • a triangle

  • an ellipse

  • a circle

  • a square


43.

A circle having centre at the origin passes through the three vertices of an equilateral triangle the length of its median being 9 units. Then the equation of that circle is

  • x2 + y2 = 9

  • x2 + y2 = 18

  • x2 + y2 = 36

  • x2 + y2 = 81


44.

1 + cos10° + cos20° + cos30° = ?

  • 4sin10°sin20°sin30°

  • 4cos5°cos10°cos15°

  • 4cos10°cos20°cos30°

  • 4sin5°sin10°sin15°


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45.

The set of all values of a such that both the points (1, 2) and (3, 4) lie on the same side of the line 3x - 5y + a = 0

  • x  IR x > 11

  • x  IR x > 11  x  IR x < 7

  • x  IR x < 7

  • ϕ


46.

If x = 1 . 33 . 6 + 1 . 3 . 53 . 6.  9 + 1 . 3 . 5 . 73 . 6.  9 . 12 + ... to infinite terms, then 9x2 + 24x = ?

  • 31

  • 11

  • 41

  • 21


47.

C437 + r = 15Cr42 - r = ?

  • C441

  • C439

  •  C438

  • C442


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48.

A container s the shape of an inverted cone. Its height is 6 m and radius is 4m at the top. If it is filled with water at the rate of 3m/min then the rate of change of height of water(in mt/min) when the water level is 3 m is

  • 34π

  • 29π

  • 16π

  • 2π


A.

34π

Let V be the volume, r be the radius and h be the height of cone at any time t Then

We have, dvdt = 3m3/minWe have to find, dhdt when h = 3mClearly, V = 13πr2h          iSince, BOD ~ BAC  By similarity criteria BOBA = ODAC 6h = 4r r = 23hNow, from eq i, we getV = 13π23h2h = 427πh3 dvdt = 427π3h2dhdt dhdt = 3 × 274π27 = 34πm/min


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49.

 If α, β, γ are the lengths of the tangents from the vertices of a triangle to its incircle. Then

  • α + β + γ = 1r2αβγ

  • α + β + γ = 1rαβγ

  • 1α + 1β + 1γ = rαβγ

  • α2 + β2 + γ2 = 2rαβγ


50.

The angle between the tangents drawn from the point (1, 2) to the ellipse 3x2 + 2y2 = 5 is

  • tan-11255

  • tan-112513

  • π4

  • π2


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