The area (in sq. units) of the region enclosed by the curves y =

Subject

Mathematics

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

11.

For a suitably chosen real constant a, let a function, f : R -  - a  R be defined byfx = a - xa + x. Further suppose that for any real number x  0 andfx  - a, fofx = x. Then f - 12 = ?

  • 3

  •  - 3

  • 13

  • - 13


12.

Let f : R  R be a function defined by f(x) = max {x, x2}. Let S denote the set of all points in R, where f is not differentiable. Then:

  • ϕ(an empty set)

  • 1

  • 0

  • 0, 1


13.

For all twice differentiable functions f : R  R, with f(0) = f(1) = f'(0) = 0

  • f''(x) = 0, for some x  (0, 1)

  • f''(x) = 0, at every point x  (0, 1)

  • f''(0) = 0

  •  f''(x)  0, at every point x  (0, 1)


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14.

The area (in sq. units) of the region enclosed by the curves y = x2 – 1 and y = 1 – x2 is equal to :

  • 83

  • 72

  • 43

  • 163


A.

83

Given curves are y = x2 – 1 and y = 1 – x2 so intersection point are (± 1, 0)

bounded area = 4011 - x2dx = 4x - x3301= 41 - 13= 83sq. units


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15.

The probabilities of three events A, B and C are given P(A) = 0.6, P(B) = 0.4 and P(C) = 0.5. If P(A  B) = 0.8, P(A  C) = 0.3, P(A  B  C) = 0.2, P(B  C)= β and P(A  B  C) = α, where 0.85  x  0.95, then β lies in the interval :

  • 0.36, 0.40

  • 0.35, 0.36

  • 0.25, 0.35

  • 0.20, 0.25


16.

The integral 12ex . x22 + logexdx = ?

  • e(2e - 1)

  • e(4e + 1)

  • 4e2 - 1

  • e(4e - 1)


17.

The common difference of the A.P. b1,b2,....,bm is 2 more than common difference of A.P. a1,a2,...,an. If a40 = –159, a100 = – 399 and b100 = a70, then b1is equal to : 

  • 127

  • 81

  • - 127

  • - 81


18.

If y = 2πx - 1csc(x) is the solution of the differential equation, dydx + pxy = 2πcscx, 0 < x < π2 then the function p(x) is equal to:

  • tanx

  • cscx

  • cotx

  • secx


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19.

Let z = x + iy be a non-zero complex number such that z2 = i |z|2, where i =  - 1, then z lies on the:

  • real axis

  • line y = x

  • line y = - x

  • imaginary axis


20.

A plane P meets the coordinate axes at A, B and C respectively. The centroid of ABC is given to be (1, 1, 2). Then the equation of the line through this centroid and perpendicular to the plane P is:

  • x - 12 = y - 11 = z - 21

  • x - 11 = y - 12 = z - 22

  • x - 11 = y - 11 = z - 22

  • x - 12 = y - 12 = z - 21


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