An ideal monoatomic gas at 27°C is compressed adiabatically t

Subject

Physics

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

1.

The dimensions of ab in the equation p = a - t2bxwhere, p is pressure, x is distance and and t is time, are

  • [M2LT-3]

  • [MT-2]

  • [LT-3]

  • [ML3T-1]


2.

Three vectors satisfy the relation A . B = 0 and A . C = 0, then A is parallel to

  • C

  • B

  • B × C

  • B . C


3.

A student is standing at a distance of 50 metre from the bus. As soon as the bus begins its motion with an acceleration of 1 ms-2,  the student starts running towards the bus with a uniform velocity u. Assuming the motion to be along a straight road, the minimum value of u, so that the student is able to catch the bus is

  • 8 ms-1

  • 5 ms-1

  • 12 ms-1

  • 10 ms-1


4.

For a given velocity, a projectile has the same range R for two angles of projection if t1 and t2 are the time of flight in the two cases, then

  • t1t2 ∝ R

  • t1t2 ∝ R2

  • t1t2  1R2

  • t1t2  1R


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5.

Weight of a body ofmass m decreases by 1 % when it is raised to height h above the earth's surface. If the body is taken to a depth h in a mine, change in its weight is

  • 0.5 % decrease

  • 2 % decrease

  • 0.5 % decrease

  • 1 % increase


6.

Which of the following sets of concurrent forces may be in equilibrium ?

  • F1 = 3 N, F2 = 5 N, F3 = 1 N

  • F1 = 3 N, F2 = 5 N, F3 = 9 N

  • F1 = 3 N, F2 = 5 N, F3 = 6 N

  • F1 = 3 N, F2 = 2 N, F3 = 15 N


7.

The displacement time graph of a particle executing SHM is as shown in the figure.

                     

The corresponding force time graph of the particle is


8.

Young's modulus of perfectly rigid body material is

  • infinite

  • zero

  • 10 × 1010 / m2

  • 1 × 1010 N/m2


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9.

An ideal monoatomic gas at 27°C is compressed adiabatically to 8/27 times of its present volume. The increase in temperature of the gas is

  • 375°C

  • 402°C

  • 175°C

  • 475°C


A.

375°C

Given : T1 = 27 + 273 = 300 K

           V1 = V (let)

           V2 = 827 V

Then for adiabatic process

T1V1γ-1 = T2V2γ-1  or  T2 = T1 V1V2γ-1

For monoatomic gas, γ = 53

So,  T2 = 300 V × 278V53 - 1 = 675 Ki.e,  T2 = 675 - 273 = 402°C

Hence, increase in temperature

= 402°C − 27°C 

= 375°C


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10.

A sample of ideal monoatomic gas is taken round the cycle ABCA as shown in the figure. The work done during the cycle is

                 

  • 3 pV

  • zero

  • 9 pV

  • 6 pV


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