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JEE Physics Solved Question Paper 2004

Multiple Choice Questions

The dimensional formula for inductance is

[ML²T^-2A^-2]
[ML²TA^-2]
[ML²T^-1A^-2]
[ML²T^-2A^-1]

A bullet moving with a speed of 100 ms^-1 can just penetrate two planks of equal thickness. Then, the number of such planks penetrated by the same bullet when the speed is doubled will be

Two bodies of masses 1 kg and 2 kg have equal momentum. Then, the ratio of their kinetic energies is

2 : 1
3 : 1
1 : 3
1 : 1

The physical quantity having the same dimensions as Planck's constant h is

linear momentum
angular momentum
Boltzmann constant
force

A balloon is rising vertically up with a velocity of 29 ms^-1 .A stone is dropped from it and it reaches the ground in 10 seconds. The height of the balloon when the stone was dropped from it is (g = 9.8ms^-1)

400 m
150 m
100 m
200 m

SI unit of permittivity is

C²m²N²
C²m^-2N^-1
C²m²N^-1
C^-1m²N^-2

Two equal forces (P each) act at a point inclined to each other at an angle of120°. The magnitude of their resultant is

When a body moves in a circular path, no work is done by the force since

force and displacement are perpendicular to each other
the force is always away from the centre
there is no displacement
there is no net force

9.
The difference between the apparent frequency of a source of sound as perceived by the observer during its approach and recession is 2% of the frequency of the source. If the speed of sound in air is 300 ms^-1, the velocity of the source is

1.5 ms^-1

12 ms^-1

6 ms^-1

3 ms^-1

3 ms^-1

When source approaches the observer, the apparent frequency heard by observer is

$n' = n (\frac{v}{v - v_{s}}) . . . . . (i)$

v_s = speed of source of sound.

During its recession, apparent frequency

$n " = n (\frac{v}{v + v_{s}}) . . . . . (ii)$

Accordingly, $n' - n " = \frac{2}{100} n (given)$

$∴ n (\frac{v}{v - v_{s}}) - n (\frac{v}{v + v_{s}}) = \frac{2}{100} n or v [\frac{v + v_{s} - v + v_{s}}{(v - v_{s}) (v + v_{s})}] = \frac{2}{100} or \frac{2 {vv}_{s}}{(v - v_{s}) (v + v_{s})} = \frac{2}{100} or 100 {vv}_{s} = v^{2} - {v_{s}}^{2}$

But speed of sound in air, v = 300 m/s

$∴ 30000 v_{s} = (300)^{2} - {v_{s}}^{2} \Rightarrow {v_{s}}^{2} + 3000 v_{s} - 90000 = 0 ∴ v_{s} = \frac{- 30000 \pm \sqrt{{(30000)}^{2} + 4 \times 90000}}{2} = \frac{30000 \pm 30006}{2} = \frac{6}{2} = 3 {ms}^{- 1} 9 (taking + ve sign only)$