The collector supply voltage is 6 V and the voltage drop across a

Subject

Physics

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

61.

If m is the mass of an electron and c is the speed of light, the ratio of the wavelength of a photon of energy E to that of the electron of the same energy is

  • c2mE

  • 2mE

  • 2mcE

  • mE


62.

The set which represents the isotope, isobar and isotone respectively is

  • (1H2, 1H3), (79Au197, 80Hg198) and (2He3, 1H2)

  • ( 2He31H1), (79Au197, 80Hg198) and (1H1, 1H3)

  • (2He3, 1H3), (1H2, 1H3) and ( 79Au197, 80Hg198)

  • (1H2, 1H3), (2He3, 1H3) and (79Au197, 80Hg198)


63.

Two samples X and Y contain equal amount of radioactive substances. If 116th of the sample X and 1256th of the sample Y, remain after 8 h, then the ratio of half periods of X and Y is

  • 2 : 1

  • 1 : 2

  • 1 : 4

  • 1 : 16


64.

Radioactive Co2760 is transformed into stable Ni2860 by emitting two γ-rays of energies

  • 1.33 MeV and 1.17 MeV in succession

  • 1.17 MeV and 1.33 MeV in succession

  • 1.37 MeV and 1.13 MeV in succession

  • 1.13 MeV and 1.37 MeV in succession


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65.

A pure semiconductor has equal electron and hole concentration of 1O16 m-3. Doping by indium increases nh to 5 x 1022 m-3. Then, the value of ne in the doped semiconductor is

  • 106 /m3

  • 1022 /m3

  • 2 × 109 / m3

  • 1019 /m3


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66.

The collector supply voltage is 6 V and the voltage drop across a resistor of 6OO Ω in the collector circuit is 0.6 V, in a transistor connected in common emitter mode. If the current gain is 20, the base current is

  • 0.25 mA

  • 0.05 mA

  • 0.12 mA

  • 0.02 mA


B.

0.05 mA

iCRC = VC

    iC = VCRC = 0.6600 = 1 mA β = iCiBor iβ = iCβ = 120 = 0.05 mA


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67.

A full-wave rectifier circuit with an AC input is shown

The output voltage across RL is represented as


68.

A carrier frequency of 1 MHz and peak value of 10 V is amplitude modulated with a signal frequency of 10 kHz with peak value of 0.5 V. Then the modulation index and the side band frequencies respectively are

  • 0.05 and ± 0.010 MHz

  • 0.5 and 1 ± 0.010 MHz

  • 0.05 and 1 ± 0.005 MHz

  • 0.5 and 1 ± 0.005 MHz


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69.

The maximum line-of-sight distance dM, between two antennas having heights hT and hR above the earth is

  • R (hT + hR)

  • 2R/hT + hR

  • RhT + 2RhR

  • 2RhT + 2RhR


70.

The frequency band used in the downlink of satellite communication is

  • 9.5 to 2.5 GHz

  • 896 to 901 MHz

  • 3.7 to 4.2 GHz

  • 840 to 935 MHz


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