What is the number of odd integers between 1000 and 9999 wit

Subject

Mathematics

Class

NDA Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

1.

Let  α and β be the roots of the equation :

x2 - 1 - 2a2x + 1 - 2a2 = 0

Under what condition does the above equation have real roots ?

  • a2 < 12

  • a2 > 12

  • a2  12

  • a2  12


2.

Let  α and β be the roots of the equation :

x2 - 1 - 2a2x + 1 - 2a2 = 0

Under what condition 1α2 + 1β2 < 1 ?

  • a2 < 12

  • a2 > 12

  • a2 > 1

  • a2  13, 12 only


3.

What is 1 + ω21 + ω = ?, where ω is cube root of unity

  • 1

  • ω

  • ω2

  • None of the above


4.

In an examination, 70% students passed in Physics80% students passed in Chemistry, 75% studentpassed in Mathematics and 85% students passed iBiology, and x% students failed in all the four subjectsWhat is the minimum value of x ?

  • 10

  • 12

  • 15

  • None of the above


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5.

For the system of linear equations 2x + 3y + 5z =97x + 3- 2z = 8 and 2x + 3y + λz = μ

Under what condition does the above system of equations have infinitely many solutions ?

  • λ = 5 and μ  9

  • λ = 5 and μ = 9

  • λ = 0 and μ = 5

  • λ = 9 and μ  5


6.

For the system of linear equations 2x + 3y + 5z =97x + 3- 2z = 8 and 2x + 3y + λz = μ

Under what condition does the above system oequations have unique solution ?

  • λ = 5, μ = 9

  • λ = 5 and  μ = 7 only

  • λ  5 and μ has any real value

  • λ has any real value and μ  9


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7.

What is the number of odd integers between 100and 9999 with no digit repeated ?

  • 2100

  • 2120

  • 2240

  • None of the above


C.

2240

All the digits that will be formed are 4 diginumbers.There are all together five odd numbers which caoccupy the last digit to form an odd number. As sooas We place an odd number in the last place we arleft with 9 numbers. But 0 can not occupy the firsplace as it reduce into 3 digit number. So, first place is occupied by 8 numbers. Second place with numbers as 0 can be included. Third place witremaining 7 numbers as repetition is not allowedThus, required number of odd numbers

= 8 x 7 X 5 = 2240


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8.

What is the greatest value of the positive integer satisfying the condition :

1 + 12 + 14 + 18 + ... + 12n - 1 < 2 - 11000 ?

  • 8

  • 9

  • 10

  • 11


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9.

2x2 + 3x - α = 0 has roots 2 and β while the equatiox2 - 3mx + 2m2 = 0 has both roots positive, where > 0 anβ > 0. What is the value of α ?

  • 12

  • 1

  • 2

  • 4


10.

2x2 + 3x - α = 0 has roots 2 and β while the equatiox2 - 3mx + 2m2 = 0 has both roots positive, where > 0 anβ > 0. If β, 2, 2m are in GP, then what is the value of βm ?

  • 1

  • 2

  • 4

  • 6


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