The solubility of in water is Sb2S3 in water is 1.0 x 1

Subject

Chemistry

Class

NEET Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

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1.

The solubility of in water is Sb2S3 in water is 1.0 x 10-5 mol/litre at 298 K .What will be its solubility product ?

  • 108 x 10-25

  • 1.0 x 10-25

  • 144 x 10-25

  • 126 x 10-25


A.

108 x 10-25

Sb2S3s mol/lit  2Sb3+2s + 3S2-3s

Solubility product

(Ksp) = [Sb3+]2 [S2]3

= (2s)2 (3s)3

= 108 s5

= 109 x (1.0 x 10-5)5

= 108 x 10-25


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2.

What will be the pH value of 0.05 M Ba(OH)2 solution ?

  • 12

  • 13

  • 1

  • 12.96


3.

Which of the following elements never show positive oxidation number ?

  • O

  • Fe

  • Ga

  • F


4.

Which of the following element is a metalloid ?

  • Bi

  • Sn

  • Ge

  • C


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5.

Ionisation depends upon :

  • pressure

  • volume

  • dilution

  • none of these


6.

The first ionisation potential is maximum for :

  • B

  • N

  • O

  • Be


7.

Which of the following salt does not get hydrolysed in water ?

  • KClO4

  • NH4Cl

  • CH3COONa

  • None of these


8.

In the reaction :

H2 + I2  2HI

In a 2 litre flask 0.4 moles of each H2 and I2 are taken .At equilibrium 0.5 moles of HI are formed .What will be the value of equilibrium constant ,Kc ?

  • 20.2

  • 25.4

  • 0.284

  • 11.11


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9.

Which among the following elements have lowest value of IE1 ?

  • Pb

  • Sn

  • Si

  • C


10.

KI and CuSO4 solution when mixed , give :

  • CuI2 + K2SO4

  • Cu2I2 + K2SO4

  • K2SO+ Cu2I2 + I2

  • K2SO+ CuI2 + I2


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