For principle quantum number n = 4, the total number of orbitals

Subject

Chemistry

Class

NEET Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

1.

Dimethyl glyoxime gives a red precipitate with Ni2+, which is used for its detection. To get this precipitate readily the best pH range is

  • < 1

  • 2-3

  • 3- 4

  • 9- 11


2.

The statement true for N3- is

  • it has a non-linear structure

  • it is called pseudohalogen

  • the formal oxidation state of nitrogen in this anion is -1

  • it is isoelectronic with NO2


3.

Shape of O2F2 is similar to that of

  • C2F2

  • H2O2

  • H2F2

  • C2H2


4.

The liquefied metal expanding on solidification is

  • Ga

  • Al

  • Zn

  • Cu.


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5.

The compound insoluble in water is

  • mercurous nitrate

  • mercuric nitrate

  • mercurous chloride

  • mercurous perchlorate.


6.

The ONO angle is maximum in

  • NO3-

  • NO2-

  • NO2

  • NO2+


7.

The dipole moment is the highest for

  • trans-2-butene

  • 1,3-dimethylbenzene

  • acetophenone

  • ethanol.


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8.

For principle quantum number n = 4, the total number of orbitals having l= 3 is

  • 3

  • 7

  • 5

  • 9


B.

7

n=4

1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 4f14

l = 3 only for f orbital.Thus the total number of orbitals for l = 3 is equal to 7 (because f contains seven orbitals).


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9.

How much energy is released when 6 moles of octane is burnt in air? Given Hf° for CO2(g) , H2O(g) and C8H18(l)  respectively are - 490, -240 and +160 kJ/mol.

  • -6.2 kJ

  • -37.4 kJ

  • -35.5 kJ

  • -20.0 kJ


10.

For the equilibrium H2O(l)  H2O(g) at 1 atm and 298K.

  • standard free energy change is equal to zero (G°= 0)

  • free energy change is less than zero (G° < 0)

  • standard free energy change is less than zero (G°< 0)

  • standard free energy change is greater than zero (G° > 0).


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