The pH of a 10-10M - NaOH solution is
10
7.01
6.99
4
B.
7.01
When the solution is very dilute, the concentration of OH- produced from water cannot be neglected. Hence,
[OH-] = 10-10 + 10-7 (obtained from water)
= 10-7 (0.001 + 1)
= 1.001 10-7
pOH = -log[OH-]
= -log(1.001 10-7)
= 7 - 0.01 = 6.99
pH = 14 - pOH
= 14 - 6.99
= 7.01
Therefore, the pH of a 10-10 - NaOH solution is 7.01
Ratio of molecular weights of A and B is then ratio of rates of diffusion will be
5 : 1
5 : 2
25 : 3
25 : 4
a/ V2 given in van der Waal's equation is for
internal pressure
inter molecular attraction
both (1) and (2)
temperature correction
C(dia) + O2 CO2; = - 395.4 kJ/ mol
C(gr) + O2 CO2; H = - 393.5 kJ/ mol
C(gr) C(dia); H = ?
-3.8
-1.9
+3.8
+1.9
The internal energy of a substance
decrease with increase in temperature
increase with increase in temperature
remains unaffected with change in temperature
calculated by E = mc2