Ratio of molecular weights of A and B is then ratio of rates of diffusion will be
5 : 1
5 : 2
25 : 3
25 : 4
a/ V2 given in van der Waal's equation is for
internal pressure
inter molecular attraction
both (1) and (2)
temperature correction
C(dia) + O2 CO2; = - 395.4 kJ/ mol
C(gr) + O2 CO2; H = - 393.5 kJ/ mol
C(gr) C(dia); H = ?
-3.8
-1.9
+3.8
+1.9
D.
+1.9
C(dia) + O2 CO2 (H = -395.4 kJ/mol) ...(1)
C(gr) + O2 CO2 (H = -393.5 kJ/mol) ...(2)
On subtarcting equation (1) from (2), we get,
C(gr) C(dia) ; H = +1.9 kJ/ mol
Since, H = -393.5 - (-395.4)
= +1.9 kJ mol-1
The internal energy of a substance
decrease with increase in temperature
increase with increase in temperature
remains unaffected with change in temperature
calculated by E = mc2