F2 formed by reacting K2MnF6 with from Chemistry NEET Year 2005

Subject

Chemistry

Class

NEET Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

1.

Among the following molecules

(i) X..eO3 (ii) X..eOF4 (iii) X..eF

those having same number of lone pairs on Xe are

  • (i) and (ii) only

  • (i) and (iii) only

  • (ii) and (iii) only

  • (i), (ii) and (iii)


2.

The diamagnetic species is

  • [Ni(CN)4]2-

  • [NiCl4]2-

  • [CoCl4]2-

  • [CoF6]2-


3.

In diborane, the two H - B - H angles are nearly

  • 60°, 120°

  • 95°, 120°

  • 95°, 150°

  • 120°, 180°


4.

U92238 emits 8 α-particles and 6 β-particles. The neutron/proton ratio in the product nucleus is

  • 60/41

  • 61/40

  • 62/41

  • 61/42


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5.

F2 formed by reacting K2MnF6 with

  • SbF5

  • MnF3

  • KSbF6

  • MnF4


A.

SbF5

F2 is formed by reacting K2MnF6 with SbF5.

K2MnF6 + 2SbF5 → 2KSbF6 + MnF312F2


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6.

The isoelectronic pair is

  • Cl2O, ICl2-

  • ICl2-, ClO2

  • IF2+, I3-

  • ClO2-, ClF2+


7.

α-Particles can be detected using

  • thin aluminium sheet

  • barium sulphate

  • zinc sulphide screen

  • gold foil


8.

Hf° (298 K) of methanol is given by the chemical equation

  • CH4 (g)12O2 (g) →CH3OH(g)

  • C (graphite) + 12O2 (g) + 2H2 → CH3OH(l)

  • C (diamond) + 12O2(g) + 2H2(g) → CH3OH(l)

  • CO(g) + 2H2 → CH3OH(l)


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9.

An endothermic reaction with high activation energy for the forward reaction is given by the diagram


10.

When 10 mL of 0.1 M acetic acid (pK= 5.0) is titrated against 10 ml of 0.1 M ammonia solution (pK= 5.0), the equivalence point occurs at pH

  • 5.0

  • 6.0

  • 7.0

  • 9.0


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