Sodium nitrate on reduction with Zn in presence of NaOH solution produces NH3. Mass of sodium nitrate absorbing 1 mole of electron will be
7.750
10.625
8.000
9.875
In transforming 0.01 mole of PbS to PbSO4, the volume of '10 volume' H2O2 required will be
11.2 mL
22.4 mL
33.6 mL
44.8 mL
D.
44.8 mL
From the equation given below,
PbS + 4H2O2 → PbSO4 + 4H2O
1 mole of PbS requires 4 moles of H2O2.
0.01 moles of PbS requires 0.04 mole of H2O2.
Now,
Weight of 0.04 mole H2O2 = 1.36 gm
And, 10 volume of H2O2 means,
1 mL of such solution of H2O2 on decomposition by heat produces 10 mL of oxygen at NTP.
H2O2 decomposes itself as,
2H2O2 → 2H2O + O2
Thus, 1 mL of 10 volume of H2O2 solution contains
= × 10 gm of H2O2 = 0.03035 gm H2O2
0.03035 gm of H2O2 is present in 1 mL of 10 volume of H2O2
1.36 gm of H2O2 present in × 1.36 mL of 10 volume of H2O2
= 44.81 mL
An unknown element forms an oxide.What will be the equivalent weight of the element if the oxygen content is 20% by weight?
16
32
8
64
2 N HCl solution will have same molar concentration as a
4.0 N H2SO4
0.5 N H2SO4
1 N H2SO4
2 N H2SO4
Addition of sodium acetate to 0.1 M acetic acid will cause
increase in pH
decrease in pH
no change in pH
change in pH that cannot be predicted
The electronic configuration 1s2, 2s22p6, 3s23p63d9 represents a
metal atom
non metal atom
non-metallic anion
metallic cation
Unusually high boiling point of water is result of
intermolecular hydrogen bonding
intramolecular hydrogen bonding
both intra and inter molecular hydrogen bonding
high specific heat
In a given shell the order of screening effect is
s > p > d > f
s > p > f > d
f > d > p > s
s < p < d < f
A catalyst is a substance which
increases the equilibrium constant of the reaction
increases equilibrium concentration of products
does not alter the reaction mechanism
changes the activation energy of the reaction