Assertion : Al forms [AlF6]3- but B does not form [BF6]3-.
Reason : B does not react with fluorine.
If both assertion and reason are true and reason is the correct explanation of assertion
If both assertion and reason are true but reason is not the correct explanation of assertion
If assertion is true but reason is false
If both assertion and reason are false
Assertion : Cu(OH)2 is soluble in NH4OH but not in NaOH.
Reason : Cu(OH)2 forms a soluble complex with NH3.
If both assertion and reason are true and reason is the correct explanation of assertion
If both assertion and reason are true but reason is not the correct explanation of assertion
If assertion is true but reason is false
If both assertion and reason are false.
2-Phenylethylbromide when heated with NaOEt, elimination takes place. No deuterium exchange takes place when the reaction is carried out in C2H5OD solvent. The mechanism will be
E1 elimination
E2 elimination
E1 cB elimination
E2 or E1cB
B.
E2 elimination
It is a primary bromide. So it will undergo elimination either by E2 or E1cB. Since there is no deuterium exchange in C2H5OD solvent, C-H bond is not broken to form carbanion. Hence the actual mechanism is E2 only.
Tincture of iodine is
aqueous solution of I2
solution of I2 in aqueous KI
alcoholic solution of I2
aqueous solution of KI
Decreasing order of stability of ions is.
(i) CH3 - H - CH3
(ii) CH3 - H - OCH3
(iii) CH3 - H - COCH3
(i) > (ii) > (iii)
(ii) > (i) > (iii)
(ii) > (iii) > (i)
(iii) > (i) > (ii)
Consider the reaction,
The correct explanation is
the product is formed due to nucleophilic substitution
the product is formed according to Saytzeff's rule
conjugated double bond product is formed, due to higher stability because of resonance stabilization
(CH3)3CO- is a better leaving group
In solvents like DMSO, acetonitrile, F- ion of dissolved NaF is more reactive than in methyl alcohol becasue
CH3OH is more polar than DMSO and CH3CN
CH3OH is less polar than DMSO and CH3CN
unsolvated F- ion is DMSO or CH3CN acts more efficiently as nucleophile
-OH group is a better leaving group than F- ion