From elementary molecular orbital theory we can deduce the electronic configuration of the singly positive nitrogen molecular ion as :
1s2 , 1s2 , 2s2 , 2s2 , 2p4 , 2p1
1s2 , 1s2 , 2s2 , 2s2 , 2p2 , 2p3
1s2 , 1s2 , 2s2 , 2s2 , 2p3 , 2p2
1s2 , 1s2 , 2s2 , 2s2 , 2p2 , 2p4
A solution contains 25% H2O , 25% C2H5OH and 50% CH3COOH by mass .The mole fraction of H2O would be :
0.25
2.5
0.502
5.03
C.
0.502
Mole fraction of H2O =
Let the total mass of solution = 100 g
Mass of H2O = 25 g
Mass of C2H5OH = 25g
Mass of CH3COOH = 50 g
Moles of H2O = = 1.388
( Molar mass of H2O = 18)
Moles of C2H5OH = = 0.543
( Molar mass of C2H5OH = 46)
Moles of CH3COOH = = 0.833
( Molar mass of CH3COOH = 60)
Total no. of moles = 1.388 + 0.543 + 0.833 = 2.764
Mole fraction of H2O = = 0.502
If the solubility of PbCl2 at 25°C is 6.3 x 10-2 mol/L , its solubility product is :
1 x 10-6
1 x 10-3
1.1 x 10-6
1.1 x 10-5
A double bond connecting two atoms .There is a sharing of :
2 electrons
1 electron
4 electrons
All electrons