If the equilibrium constants of the following equilibria,SO2 + 1/

Subject

Chemistry

Class

NEET Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

1.

The pH of an aqueous solution of CH3COONa of concentration C(M) is given by:

  • 7 - 1/2 pKa - 1/2 log C

  • 1/2 pKw + 1/2 pKb + 1/2 log C

  • 1/2 pKw - 1/2 pKb - 1/2 log C

  • 1/2 pKw - pKa + 1/2 log C


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2.

If the equilibrium constants of the following equilibria,

SO2 + 1/2O2  SO3 and 2SO3  2SO2 + O2

are given by K1 and K2 respectively, which of the following relations is correct?

  • K2 = (1/K1)2

  • K1 = (1/K3)3

  • K2 = (1/K1)

  • K2 = (K1)2


A.

K2 = (1/K1)2

SO2 + 1/2 O2 SO3

K1[SO3][SO2][O2]1/2

2SO3 2SO2 + O2

K2[SO2]2[O2][SO3]2

Obviously, K2 = (1/K1)2


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3.

The energy of an electron in first Bohr orbit of H-atom is-13.6 eV. The possible energy value of electron in the excited state of Li2+ is:

  • - 122.4 eV

  • 30.6 eV

  • - 30.6 eV

  • 13.6 eV


4.

The amount of the heat released when 20 mL 0.5 M NaOH is mixed with 100 ml 0.1 M HCl is x kJ. The heat of neutralisation is:

  • - 100 x kJ/mol

  • - 50 x kJ/mol

  • + 100 x kJ/mol

  • + 50 x kJ/mol


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5.

Which one of the following has the lowest ionisation energy?

  • 1s2 , 2s2 , 2p6

  • 1s2 , 2s2 , 2p6 , 3s1

  • 1s2 , 2s2 , 2p5

  • 1s2 , 2s2 , 2p3


6.

2 g of metal carbonate is neutralised completely by 100 mL of 0.1 N HCI. The equivalent weight of metal carbonate is:

  • 50

  • 100

  • 150

  • 200


7.

An electric current is passed through an aqueous solution of a mixture of alanine (isoelectric point 6.0), glutamic acid (3.2) and arginine (10.7) buffered at pH 6. What is the fate of the three acids?

  • Glutamic acid migrates to anode at pH 6. Arginine is present as a cation and migrates to the cathode. Alanine in a dipolar ion remains uniformly distributed in solution

  • Glutamic acid migrates to cathode and others remain uniformly distributed in solution

  • All three remain uniformly distributed in solution

  • All three move to cathode


8.

The representation of the ground state electronic configuration of He by box-diagram as 

is wrong because it violates:

  • Heisenberg's uncertainty principle

  • Bohr's quantization theory of angular momenta

  • Pauli exclusion principle

  • Hund's rule


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9.

The electronic transitions from n = 2 to n = 1 will produce shortest wavelength in (where n = principal quantum state)

  • Li2+

  • He+

  • H

  • H+


10.

In the following electron-dot structure calculate the formal charge from left to right nitrogen atom; N....=N=N.... :

  • -1 , -1 , +1

  • -1 , +1 , -1

  • +1 , -1 , -1

  • +1 , -1 , +1


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