At 250 molar conductance of 0.1 molar aqueous solutions of ammon

Subject

Chemistry

Class

NEET Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

11.

The basic structural unit of silicates is 

  • SiO-

  • SiO24-

  • SiO32-

  • SiO32-

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12.

Which of the following is electron deficient

  • (CH3)2

  • (SiH3)2

  • (BH3)2

  • (BH3)2

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13.

Structure of the compound whose IUPAC name is 3-ethyl-2-hydroxy-4-methylhex-3-en-5-ynoic acid is

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14.

The order of stability of the following tautomeric compound is 

  • I>Ii>III

  • III > II>I

  • Ii> I> III

  • Ii> I> III

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15.

The radical  because it has

  • 6 p -orbitals and 6 unpaired electrons

  • 7 p- orbitals and 6 unpaired electrons

  • 7 p- orbitals and 7 unpaired electrons

  • 7 p- orbitals and 7 unpaired electrons

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16.

The structure of isobutyl group in an organic compound is

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17.

What is the activation energy for a reaction if its rate doubles when the temperature is raised from 200C to 350C ?(R=8.314 J mol-1 K-1).

  • 342 kJ mol-1

  • 269 kJ mol-1

  • 34.7 kJ mol-1

  • 34.7 kJ mol-1

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18.

At 250 molar conductance of 0.1 molar aqueous solutions of ammonium hydroxide is 9.54 ohm-1 cm2 mol-1 and at infinite dilution, its molar conductance is 238 ohm-1 cm2 mol-1. The degree of ionisation of ammonium hydroxide at the same concentration and temperature is 

  • 2.080%

  • 20.800%

  • 4.008%

  • 4.008%


C.

4.008%

Given molar conductance at 0.1 M concentration,
λc = 9.54 Ω-1 cm2 mol-1
Molar conductance at infinite dilution,

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19.

A button cell used in watches functions as following
Zn space left parenthesis straight s right parenthesis space plus Ag subscript 2 straight O space left parenthesis straight s right parenthesis space plus straight H subscript 2 straight O space left parenthesis straight l right parenthesis space rightwards harpoon over leftwards harpoon space 2 space Ag space left parenthesis straight s right parenthesis space plus Zn to the power of 2 plus end exponent space left parenthesis aq right parenthesis space plus 2 OH to the power of minus space left parenthesis aq right parenthesis
If space half minus cell space potentials space are
Zn to the power of 2 plus end exponent space left parenthesis aq right parenthesis space plus 2 straight e to the power of minus space rightwards arrow space Zn left parenthesis straight s right parenthesis semicolon space straight E to the power of 0 equals space minus 0.76 space straight V
Ag subscript 2 straight O space left parenthesis straight s right parenthesis space plus straight H subscript 2 straight O space left parenthesis straight l right parenthesis space plus 2 straight e to the power of minus rightwards arrow 2 Ag space left parenthesis straight s right parenthesis space plus 2 OH to the power of minus space left parenthesis aq right parenthesis space left parenthesis straight E to the power of 0 space equals space 0.34 space straight V right parenthesis
The cell potential will be

  • 1.10 V

  • 0.42 V

  • 0.84 V

  • 0.84 V

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20.

The number of carbon atoms per unit cell of diamond unit cell is

  • 4

  • 8

  • 6

  • 6

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