When phenol is treated with D2SO4 /D2O, some of the hydrogens get

Subject

Chemistry

Class

NEET Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

51.

Cupric compounds are more stable than their cuprous counterparts in solid state. This is because

  • the endothermic character of the 2nd IP of Cu is not so high

  • size of Cu2+ is less than Cu+

  • Cu2+ has stable electronic configuration as compared to Cu+

  • the lattice energy released for cupric compounds is much higher than Cu+


52.

The correct statement regarding the following compounds is

  • all three compounds are chiral

  • only I and II are chiral

  • I and III are diastereomers

  • only I and III are chiral


53.

In the following reaction, the product E is


54.

The intermediate J in the following Wittig reaction is


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55.

Among the following compounds, the one(s) that gives (give) effervescence with aqueous NaHCO3 solution is (are)

(CH3CO)2 I CH3COOHII  PhOHIII  CH3COCHOIV

  • I and II

  • I and III

  • Only II

  • I and IV


56.

An amine C3H9N reacts with benzene sulphonyl chloride to form a white precipitate which is insoluble in aq. NaOH. The amine is


57.

The number of amino acids and number of peptide bonds in a linear tetrapeptide (made of different amino acids) are respectively

  • 4 and 4

  • 5 and 5

  • 5 and 4

  • 4 and 3


58.

In DNA, the consecutive deoxynucleotides are connected via

  • phosphodiester linkage

  • phosphomonoester linkage

  • phosphotriester linkage

  • amide linkage


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59.

The reaction of aniline with chloroform under alkaline conditions leads to the formation of 

  • phenylcyanide

  • phenylisonitrile

  • phenylcyanate

  • phenylisocyanate


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60.

When phenol is treated with D2SO4 /D2O, some of the hydrogens get exchanged. The final product in this exchange reaction is


A.

In acidic medium, phenol exists in following resonating structures.

Since, o/p positions are electron rich sites, so electrophile will attack on these site, i.e.,
hydrogen of these sites get exchanged by D (deuterium).

Hence, the final product of the reaction is 

It is formed as -


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