The compressibility of a gas is less than unity at STP, therefore,
Vm > 22.4 L
Vm < 22.4 L
Vm = 22.4
Vm = 44.8 L
Among the following set of quantum numbers, the impossible set is
n | l | m | s |
3 | 2 | -3 | -1/2 |
n | l | m | s |
4 | 0 | 0 | 1/2 |
n | l | m | s |
5 | 3 | 0 | -1/2 |
n | l | m | s |
3 | 2 | -2 | 1/2 |
A.
n | l | m | s |
3 | 2 | -3 | -1/2 |
Principal quantum number = n
Azimuthal quantum number = l = 0 to (n-1)
Magnetic quantum number = m = -l to +1
Spin quantum number = s = +1/2 or -1/2
Now,
(i) In first option the given values are,
n=3; l=2; m=-3; s=-1/2
So according to Azimuthal quantum number
l = 0 to (n-1) = 0 to 2 = here it is 2 which is permissible
m = -l to +l = -2 to +2 = here it is 3 which is not permissible
s = +1/2 or -1/2 = here it is -1/2 whch is permissible
(ii) In the second option given values are,
n = 4; l = 0, m = 0; s= 1/2
So according to Azimuthal quantum number
l = 0 to (n-1) = 0 to 3 = here it is 0 which is permissible
m =-l to +l = -3 to +3 = here it is 0 which is permissible
s = +1/2 or -1/2 = here it is 1/2 whch is permissible
(iii) In the third option given values are,
n =5; l = 3; m= 0; s= -1/2
So according to Azimuthal quantum number
l = 0 to (n-1) = 0 to 4 = here it is 3 which is permissible
m = -l to +l = -4 to +4 = here it is 0 which is permissible
s = +1/2 or -1/2 = here it is -1/2 whch is permissible
(iv) it the forth option given values are,
n=3; l =2; m=-2; s = 1/2
So according to Azimuthal quantum number
l = 0 to (n-1) = 0 to 2 = here it is 2 which is permissible
m = -l to +l = -2 to +2 = here it is 2 which is permissible
s = +1/2 or -1/2 = here it is -1/2 whch is permissible
Among the following compounds, which compound is polar as well as exhibit sp2-hybridisation by the central atom.
H2CO3
SiF4
BF4
HClO3
The energy released when 6 moles of octane is burnt in air will be [Given, ΔHf for CO2 (g). H2O(g) and C8H18 (l), respectively are -490, -240 and +160J/mol]
-37.4 kJ
-20 kJ
-6.2 kJ
-35.5 kJ
When 750 mL of 0.5 M HCl is mixed with 250 mL of 2 M NaOH solution, the value of pH will be
pH = 7
pH > 7
pH < 7
pH = 0
Match the type of series given in Column I with the wavelength range given in Column II and choose the correct option.
Column I | Column II | ||
A | Lyman | 1. | Ultraviolet |
B. | Paschen | 2. | Near-infrared |
C. | Balmer | 3. | Far Infrared |
D. | Pfund | 4. | Visible |
A | B | C | D |
1 | 2 | 4 | 3 |
A | B | C | D |
4 | 3 | 1 | 2 |
A | B | C | D |
3 | 1 | 2 | 4 |
A | B | C | D |
4 | 3 | 2 | 1 |
The electrons identified by quantum numbers n and l, are as follows
n = 4, l = 0
n =3, l= 2
If we arrange them in order of increasing energy, i.e., from lowest to highest, the correct order is
IV<II<III<I
II<IV<I<III
I < III < II < IV
III < I < IV < II
Which of the following is the correct order of stability for the given superoxides?
KO2 < RbO2 < CsO2
CsO2 < RbO2<KO2
RbO2
KO2 < CsO2 <RbO2