Which of the following is the correct order of stability for the

Subject

Chemistry

Class

NEET Class 12

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

1.

The compressibility of a gas is less than unity at STP, therefore,

  • Vm > 22.4 L

  • Vm < 22.4 L

  • Vm = 22.4

  • Vm = 44.8 L


2.

Among the following set of quantum numbers, the impossible set is

  • n l m s
    3 2 -3 -1/2
  • n l m s
    4 0 0 1/2
  • n l m s
    5 3 0 -1/2
  • n l m s
    3 2 -2 1/2

3.

Which of the following is least soluble in water?

  • C2H6

  • CH3OH

  • CH3NH2

  • C6H5OH


4.

Among the following compounds, which compound is polar as well as exhibit sp2-hybridisation by the central atom.

  • H2CO3

  • SiF4

  • BF4

  • HClO3


Advertisement
5.

The energy released when 6 moles of octane is burnt in air will be [Given, ΔHf for CO2 (g). H2O(g) and C8H18 (l), respectively are -490, -240 and +160J/mol]

  • -37.4 kJ

  • -20 kJ

  • -6.2 kJ

  • -35.5 kJ


6.

When 750 mL of 0.5 M HCl is mixed with 250 mL of 2 M NaOH solution, the value of pH will be

  • pH = 7

  • pH > 7

  • pH < 7

  • pH = 0


7.

The most stable carbonium ion among the following is

  • C6H5 -CH2C+H2

  • CH3CH2+

  • C6H5 -C+-C6H5

  • C6H5C+H2


8.

Match the type of series given in Column I with the wavelength range given in Column II and choose the correct option.
Column I Column II
A Lyman 1. Ultraviolet
B. Paschen 2. Near-infrared
C. Balmer 3. Far Infrared
D. Pfund 4. Visible

  • A B C D
    1 2 4 3
  • A B C D
    4 3 1 2
  • A B C D
    3 1 2 4
  • A B C D
    4 3 2 1

Advertisement
9.

The electrons identified by quantum numbers n and l, are as follows

  1. n =4, l=1
  2. n = 4, l = 0

  3. n =3, l= 2

  4. n = 3, l = 1

If we arrange them in order of increasing energy, i.e., from lowest to highest, the correct order is

  • IV<II<III<I

  • II<IV<I<III

  • I < III < II < IV

  • III < I < IV < II


Advertisement

10.

Which of the following is the correct order of stability for the given superoxides?

  • KO2 < RbO2 < CsO2

  • CsO2 < RbO2<KO2

  • RbO2

  • KO2 < CsO2 <RbO2


A.

KO2 < RbO2 < CsO2

With a progressive increase in the size of alkali metal ions, the stability of superoxides increases because the size of superoxide ion is large and large cation can be stabilised more by large anion. 

Therefore, the order of stability is

KO2 <RbO2 < CsO2


Advertisement
Advertisement