A ball is released from certain height which losses 50% of its kinetic energy on striking the ground it will contain a height again
of initial height
of initial height
th of initial height
None of the above
A particle moves towards east for 2 s with velocity 15 m/s and move towards north for 8 s with velocity 5 m/s. Then, average velocity of the particle is
1 m/s
5 m/s
7 m/s
10 m/s
Match the following
Angular momentum | 1. [M-1 L2 T-2 ] |
B. Torque | 2 [M1 L2 T-2 |
C. Gravitational constant | 3.[M1 L2 T-2] |
D. Tension | 4.[M1 L2 T-1] |
C- 2, D - 1
A - 4, B - 3
A - 3, C -2
B-2, A - 1
B.
A - 4, B - 3
Dimensions of Torque = [M2 L2 T-2]
Dimension of angular momentum = [ M1 L2 T-1]
∴ Relation A-4 ,B -3 is right.
If we increase kinetic energy of a body 300%, then per cent increase in its momentum is
50%
300%
100%
150%
Change in acceleration due to gravity is same upto a height h from each other the earth surface and below depth x then relation between x and his ( h and x<<<Re )
x = h
x = 2h
x =
x = h2
Three points charges +q, -2q and +q are placed at points (x=0, y=a, z=0), ( x=0, y=0, z=0 ) and (x=a, y=0, z=0), respectively. The magnitude and direction of the electric dipole moment vector of this charge assembly are
√2 qa along + y direction
√2 qa along the line joining point
qa along the line joining points (x = 0,y = 0, z = 0) and (x = a, y = a, z = 0)
√2 qa along + x direction
A block B is pushed momentarily along a horizontal surface with an initial velocity v. If is the coefficient of vlicling friction between B and the surface, block B will come to rest after a time
A particle of mass M and charge Q moving with velocity v describes a circular path of radius R when subjected to a uniform transverse magnetic field of induction B. The work done by the field, when the particle completes one full circle, is
zero
A particle of mass 100 g is thrown vertically upward with a speed of 5 m/s. The work done by the force of gravity during the time the particle goes up is
-0.5 J
-1.25 J
1.25 J
0.5 J